python 将列表中的指定位置的两个元素对调
定义一个列表，并将列表中的指定位置的两个元素对调。
例如，对调第一个和第三个元素：
对调前 : list = [23, 65, 19, 90], pos1 = 1, pos2 = 3 对调后 : [19, 65, 23, 90]
实例 1
def swappositions(list, pos1, pos2):
list[pos1], list[pos2] = list[pos2], list[pos1]
return list
list = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swappositions(list, pos1-1, pos2-1))
list[pos1], list[pos2] = list[pos2], list[pos1]
return list
list = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swappositions(list, pos1-1, pos2-1))
以上实例输出结果为：
[19, 65, 23, 90]
实例 2
def swappositions(list, pos1, pos2):
first_ele = list.pop(pos1)
second_ele = list.pop(pos2-1)
list.insert(pos1, second_ele)
list.insert(pos2, first_ele)
return list
list = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swappositions(list, pos1-1, pos2-1))
first_ele = list.pop(pos1)
second_ele = list.pop(pos2-1)
list.insert(pos1, second_ele)
list.insert(pos2, first_ele)
return list
list = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swappositions(list, pos1-1, pos2-1))
以上实例输出结果为：
[19, 65, 23, 90]
实例 3
def swappositions(list, pos1, pos2):
get = list[pos1], list[pos2]
list[pos2], list[pos1] = get
return list
list = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swappositions(list, pos1-1, pos2-1))
get = list[pos1], list[pos2]
list[pos2], list[pos1] = get
return list
list = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swappositions(list, pos1-1, pos2-1))
以上实例输出结果为：
[19, 65, 23, 90]
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