AES在iOS(Obj-C)和Android(Java)中获得不同的结果

我是这种加密的完全新手,但我有一个Java应用程序和iOS,我希望他们都能够将文本转换成相同的结果.我用AES.
我找到了这些代码,当然稍作修改,但它们会返回不同的结果

iOS代码：

- (NSData *)AESEncryptionWithKey:(NSString *)key {    
    unsigned char keyPtr[kCCKeySizeAES128] = { 'T', 'h', 'e', 'B', 'e', 's', 't', 'S', 'e', 'c', 'r','e', 't', 'K', 'e', 'y' };
    size_t bufferSize = 16;
    void *buffer = malloc(bufferSize);
    size_t numBytesEncrypted = 0;
    const char iv2[16] = {  65, 1, 2, 23, 4, 5, 6, 7, 32, 21, 10, 11, 12, 13, 84, 45 };
    CCCryptorStatus cryptStatus = CCCrypt(kCCEncrypt,
                                          kCCAlgorithmAES128,
                                          kCCOptionECBMode | kCCOptionPKCS7Padding,,
                                          keyPtr,
                                          kCCKeySizeAES128,
                                          iv2,
                                          @"kayvan",
                                          6,
                                          dataInLength,
                                          buffer,
                                          bufferSize,
                                          &numBytesEncrypted);


    if (cryptStatus == kCCSuccess) {
        return [NSData dataWithBytesNoCopy:buffer length:numBytesEncrypted];
    }

    free(buffer);
    return nil;
}

而Java代码是：

public static void main(String[] args) throws Exception {
    String password = "kayvan";
    String key = "TheBestSecretKey";
    String newPasswordEnc = AESencrp.newEncrypt(password, key);
    System.out.println("Encrypted Text : " + newPasswordEnc);
}

在另一个java类(AESencrp.class)中,我有：

public static final byte[] IV = { 65, 1, 2, 23, 4, 5, 6, 7, 32, 21, 10, 11, 12, 13, 84, 45 };
public static String newEncrypt(String text, String key) throws Exception {
    Cipher cipher = Cipher.getInstance("AES/CBC/PKCS5Padding");
    byte[] keyBytes= new byte[16];
    byte[] b= key.getBytes("UTF-8");
    int len = 16; 
    System.arraycopy(b, 0, keyBytes, 0, len);
    SecretKeySpec keySpec = new SecretKeySpec(keyBytes, "AES");
    IvParameterSpec ivSpec = new IvParameterSpec(IV);
    System.out.println(ivSpec);
    cipher.init(Cipher.ENCRYPT_MODE,keySpec,ivSpec);
    byte[] results = cipher.doFinal(text.getBytes("UTF-8"));
    String result = DatatypeConverter.printBase64Binary(results);
    return result;
}

我想要加密的字符串是kayvan,键是TheBestSecretKey.和Base64编码后的结果是：

对于iOS：9wXUiV ChoLHmF6KraVtDQ ==

for Java：/ s5YyKb3tDlUXt7pqA5OFA ==

我现在应该怎么做？

解决方法:

我用iOS / Android / Node.js AES256相同的结果编码,https://gist.github.com/m1entus/f70d4d1465b90d9ee024

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