--4.怎么解决,解决方案如下
(1)
[sql] view plaincopy- SQL> select to_nmber(to_char(0.99)) from dual;
- TO_NUMBER(TO_CHAR(0.99))
- ------------------------
- 0.99
- SQL> select to_char(num,‘fm999999990.999999999‘) from ml_test;
- TO_CHAR(NUM,‘FM999999990.99999
- ------------------------------
- 0.42124
- 0.421246543
- 65432.42124324
- 4.62124
(2)使用case when 或 decode函数,取第一位是否为".", 补0 ,就ok了
[sql] view plaincopy
- SQL> select to_char(num,‘999999999.999999999‘) from ml_test;
- TO_CHAR(NUM,‘999999999.9999999
- ------------------------------
- .421240000
- .421246543
- 65432.421243240
- 4.621240000
- SQL> select to_char(num) from ml_test;
- TO_CHAR(NUM)
- ----------------------------------------
- .42124
- .4212465434
- 65432.42124324
- 4.62124
- SQL> select to_char(0.99) from dual;
- TO_CHAR(0.99)
- -------------
- .99
oracle查询不显示小数点前的0
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