一、查询执行最慢的sql
select *
from (select sa.SQL_TEXT,
sa.SQL_FULLTEXT,
sa.EXECUTIONS "执行次数",
round(sa.ELAPSED_TIME / 1000000, 2) "总执行时间",
round(sa.ELAPSED_TIME / 1000000 / sa.EXECUTIONS, 2) "平均执行时间",
sa.COMMAND_TYPE,
sa.PARSING_USER_ID "用户ID",
u.username "用户名",
sa.HASH_VALUE
from v$sqlarea sa
left join all_users u
on sa.PARSING_USER_ID = u.user_id
where sa.EXECUTIONS > 0
order by (sa.ELAPSED_TIME / sa.EXECUTIONS) desc)
where rownum <= 50;
二、查询次数最多的 sql
select *
from (select s.SQL_TEXT,
s.EXECUTIONS "执行次数",
s.PARSING_USER_ID "用户名",
rank() over(order by EXECUTIONS desc) EXEC_RANK
from v$sql s
left join all_users u
on u.USER_ID = s.PARSING_USER_ID) t
where exec_rank <= 100;
oracle查看执行最慢与查询次数最多的sql语句
标签:comm and left join select round 查看 join _id where
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